The following two-way contingency table gives the breakdown of the population in
ID: 3272925 • Letter: T
Question
The following two-way contingency table gives the breakdown of the population in a particular locale according to party affiliation (A, B, C, or None) and opinion on a bond issue:
A person is selected at random. Find the probability of each of the following events.
The person is affiliated with party B.
The person is affiliated with some party.
The person is in favor of the bond issue.
The person has no party affiliation and is undecided about the bond issue.
The person has no party affiliation or is in favor of the bond issue.
Affiliation Option Favors Opposes Undecided A 0.12 0.09 0.07 B 0.16 0.12 0.14 C 0.04 0.03 0.06 None 0.08 0.06 0.03Explanation / Answer
Favors Opposes Undecided Total
A 0.12 0.09 0.07 0.28
B 0.16 0.12 0.14 0.42
C 0.04 0.03 0.06 0.13
None 0.08 0.06 0.03 0.17
-------------------------------------------------------------------------------------------------------------
Total 0.40 0.30 0.30 1.00
(a) P(Party B) = 0.42
(b) P(some party) = 0.28 + 0.42 + 0.13 = 0.83
(c) P(Favor) = 0.40
(d) P(No Party & Undecided) = 0.03
(e) P(No party OR Favor) = P(No party) + P(Favor) - P(No party & favor)
= 0.17 + 0.40 - 0.08 = 0.49
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.