In a study of the effectiveness of a new, lighter, running shoe you have designe
ID: 3274402 • Letter: I
Question
In a study of the effectiveness of a new, lighter, running shoe you have designed, you give the shoe to 1068 runners, and compare them with a sample of 2127 runners who don’t receive the shoe. 698 of the sample of runners with the shoes won their race, compared to 639 runners in the control condition. Test the prediction that the shoe is significantly more effective in enhancing running performance at the alpha = .05 level.
Because this data has two sets of contingencies (won versus not win), and (shoes versus no shoes), I can set up a 2 x 2 contingency table and use the Chi-square distribution.
The critical value of my statistic at 1 degree of freedom is 3.84
The computed value of my statistic is 364.35
I must reject the null hypothesis that the proportion of people who win with the shoe is the same as the proportion of people who win without the shoe.
All the above
A.Because this data has two sets of contingencies (won versus not win), and (shoes versus no shoes), I can set up a 2 x 2 contingency table and use the Chi-square distribution.
B.The critical value of my statistic at 1 degree of freedom is 3.84
C.The computed value of my statistic is 364.35
D.I must reject the null hypothesis that the proportion of people who win with the shoe is the same as the proportion of people who win without the shoe.
E.All the above
Explanation / Answer
Ho: no relation b/w X and Y OR X and Y are independent
Ha: exists a relation b/w X and Y OR X and Y are dependent
level of significance, = 0.05
test statistic =364.3457 ~ 364.35
degree of freedom =(r-1)*(c-1)=(2-1)*(2-1)=1
critical value at df=1 at alpha =0.05 is 3.845
test statistic value > critical value
hence we reject Null hypothesis.
option E .ALL THE ABOVE
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