There are 10 math majors and 10 CS majors, and they have to form teams of two fo
ID: 3274429 • Letter: T
Question
There are 10 math majors and 10 CS majors, and they have to form teams of two for a competition. If each arrangement is equally likely, what is the probability that no team is mixed, i.e. each of the 10 teams-of-two either consists of both CS majors or both math majors.There are 10 math majors and 10 CS majors, and they have to form teams of two for a competition. If each arrangement is equally likely, what is the probability that no team is mixed, i.e. each of the 10 teams-of-two either consists of both CS majors or both math majors.
There are 10 math majors and 10 CS majors, and they have to form teams of two for a competition. If each arrangement is equally likely, what is the probability that no team is mixed, i.e. each of the 10 teams-of-two either consists of both CS majors or both math majors.
Explanation / Answer
The required probability = [(10C2 + 10C2)/20C2] , C denotes the combination.
Hence, required probability = (45+45)/190 = 90/190 = 0.4637. (Ans).
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