Consider two boxes containing marbles of differing colors BOXA 2 red 3 green BOX
ID: 3275733 • Letter: C
Question
Explanation / Answer
box A box B red 2 3 green 3 1 marbles 5 4 in box A: P(marbles will be of same color) =(1/2)*(COMBIN(2,2)+COMBIN(3,2))/COMBIN(5,2) 0.2 in box B: P(marbles will be of same color) =(1/2)*(COMBIN(3,2)+0)/COMBIN(4,2) 0.25 hence, required prob.: =0.2+0.25 0.45
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