Questions 13-14. Suppose a box contains 10 red balls, 10 green balls, and 10 ora
ID: 3275987 • Letter: Q
Question
Questions 13-14. Suppose a box contains 10 red balls, 10 green balls, and 10 orange balls. You will be choosing 3 balls from the box without replacement 13. What is the probability of drawing an orange on the first draw and a red on the second draw? [7 pts b) 0.1000 c) 0.1034 d) 0.1149 e) None of the answers is correct to the fourth decimal place. the above question Do Question i, as if you are starting with a brand new first draw. Question 14. 14. What is the probability of drawing an orange on the third draw? 7 pts a) 0.1987 b) 0.3333 c) 0.4599 d) 0.6667Explanation / Answer
Ans:
10 red,10 green,10 orange
13) Orange on first and red on second draw
(10/30)*(10/29)=0.1149
Option d is correct.
14)Orange on third draw
=red on first,green on second and orange in third+green on first,red on second and orange in third+2 red and then orange+2 green and then orange+orange on first second and third
=2*10/30)*(10/29)*(10/28)+(10/30)*(9/29)*(10/28)+(10/30)*(9/29)*(10/28)+(10*9*8)/(30*29*28)
=2*0.0411+2*0.037+0.03
=0.1922
Option a should be correct.
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