in a certarprocess gas ends in its original thermodynamic state (initial and fin

Question

in a certarprocess gas ends in its original thermodynamic state (initial and final states are the same). Of the following which is possible as the net result of the process? LAIt is adiabatic and the gas does 50of work . The gas does no work but absorbs soof energy as heat C The gas does no work but rejects 50 J of energy as heat O. The gas rejects 50 J of energy as heat and does 501 of work E,The gas absorbs 50 of energy as heat and does 50ot work There was a piece of ice with mass m-1 kg at the temperature T-223.16 K in a calorimeter. Some amount of heat was transferred to the ice. After the equillibrium 7 was reached, 1/3 kg of ice and 2/3 kg of water were found in the calorimeter many enerzy as heat was transferring to ice? To neglect change of volume during heating Find of pressure for an ideal gas. Radom variable x can have any values from interval [-0.5, 1.5) with density of probability that is plaxj-Clx -0.5)

Explanation / Answer

7. Since in the given thermodynamic system, the initial and final state of gas are same, it means that the amount of heat absorbed or released by the system is equal to the amount of work done on or by the system. Hence the temperature, pressure, volume and energy of the system will not change and the state remains same.

So, the answer is (e) that is, the gas absorbs 50J of heat anddoes 50 J of work.

8. The amount of heat transferred to the system is equal to the difference between the total heat and the heat contained within the piece of the ice.

Specific heat of water = 4.187 kJ/kg-K

specific heat of ice = 2.108 kJ/kg-K

Temperature of system initially = 0 C = 273.15 K

so, heat transferred = (2/3)*4.187*(273.13)+(1/3)*2.108*(273.15-223.16)-1*2.108*(273.15-223.16)

= 139.539 + 35.126 - 105.379

= 69.286 kJ

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