I have 3 questions I need all of the to be answered please 1) A mini bike compan

Question

I have 3 questions I need all of the to be answered please 1) A mini bike company needs a slab of A36 steel, 250 thick in the following configuration (shaded area shown below). The slab is to weigh 1.86 pounds. Use 2836 Ibs/cu in as density of steel. 4.00 50.0 A- What is the length of the top of the shaded area (the bottom of the unshaded triangle)? B- What would be the area of the shaded section? Calculate using the density. C-What is dimension H? D- What is dimension W? Sec 1 Pages 1 of 3 Words: 169 of 233 MacBook Air

Explanation / Answer

let the length of the bottom of the unshaded area be l

thickness t = 0.25 in

weight, W = 1.86 pounds

density, rho = 0.2836 pounds/in^3

a. from trigonometry

tan(50) = l/4

l = 4*tan(50)= 4.767 in

b. let area of shaded portion be A

then A*t = volume = V

and weight of slab, W = rho*V

0.2836 * A*0.25 = 1.86

A = 26.2341 in^2

c. area of trapezium = 0.5(l + w)H = A

0.5(4.767 + w)H = 26.2341

also, tan(50) = w/(H + 4)

1.1917H + 4.767 = w

so, 0.5(4.767 + 1.1917H + 4.767)H = 26.2341

4.767H + 0.5955H^2 - 26.2341 = 0

solving for H

H = 3.748 in

d. w = 1.1917H + 4.767 = 9.23113 in

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