A froth flotation process is used to concentrate copper ore. It is a two-stage p

Question

A froth flotation process is used to concentrate copper ore. It is a two-stage process that involves one rougher stage and one cleaner stage. The cleaner tailings return to the rougher flotation. Both stages are nonreactive unit operations that operate at steady-state. The analytical profile of the entire flotation circuit is: - The rougher flotation feed grade is 0.50% Cu. - The rougher concentrate grade is 11.8% Cu. - The rougher tailings contain 0.09% Cu. - The cleaner (final) concentrate grade is 31.0% Cu. - The cleaner tailings contain 4.7% Cu.
Part A - Overall Copper Recovery Calculate the overall copper recovery for the process.
Part B - Cleaner Copper Recovery Calculate the copper recovery in the cleaner flotation operation.
Part C - Cleaner Tailings Assuming that the flotation process treats 250 tons/hr of copper ore, calculate the circulating load (in tons/hr) of cleaner tailings that return to the rougher flotation under steady-state operation. A froth flotation process is used to concentrate copper ore. It is a two-stage process that involves one rougher stage and one cleaner stage. The cleaner tailings return to the rougher flotation. Both stages are nonreactive unit operations that operate at steady-state. The analytical profile of the entire flotation circuit is: - The rougher flotation feed grade is 0.50% Cu. - The rougher concentrate grade is 11.8% Cu. - The rougher tailings contain 0.09% Cu. - The cleaner (final) concentrate grade is 31.0% Cu. - The cleaner tailings contain 4.7% Cu.
Part A - Overall Copper Recovery Calculate the overall copper recovery for the process.
Part B - Cleaner Copper Recovery Calculate the copper recovery in the cleaner flotation operation.
Part C - Cleaner Tailings Assuming that the flotation process treats 250 tons/hr of copper ore, calculate the circulating load (in tons/hr) of cleaner tailings that return to the rougher flotation under steady-state operation. A froth flotation process is used to concentrate copper ore. It is a two-stage process that involves one rougher stage and one cleaner stage. The cleaner tailings return to the rougher flotation. Both stages are nonreactive unit operations that operate at steady-state. The analytical profile of the entire flotation circuit is: - The rougher flotation feed grade is 0.50% Cu. - The rougher concentrate grade is 11.8% Cu. - The rougher tailings contain 0.09% Cu. - The cleaner (final) concentrate grade is 31.0% Cu. - The cleaner tailings contain 4.7% Cu.
Part A - Overall Copper Recovery Calculate the overall copper recovery for the process.
Part B - Cleaner Copper Recovery Calculate the copper recovery in the cleaner flotation operation. Part B - Cleaner Copper Recovery Calculate the copper recovery in the cleaner flotation operation.
Part C - Cleaner Tailings Assuming that the flotation process treats 250 tons/hr of copper ore, calculate the circulating load (in tons/hr) of cleaner tailings that return to the rougher flotation under steady-state operation. Part C - Cleaner Tailings Assuming that the flotation process treats 250 tons/hr of copper ore, calculate the circulating load (in tons/hr) of cleaner tailings that return to the rougher flotation under steady-state operation.

Explanation / Answer

(a) Let the weight percentage of feed = x

Let the weight percentage of concentrate = y

Let the rougher flotation feed = a

Let rougher concentrate grade =b.

Let the rougher tailings contain = c

(Part A ) the overall copper recovery for the process = 100*(b/a)(a-c/b-c)

= 100*(11.8/0.50) * [(0.50-0.09)/(11.8-0.09)

= 100*23.6*0.035

= 82.63 % of Cu

(Part B ) The rougher concentrate grade for the cleaner copper recovery is "a" = 11.8% of Cu

Cleaner Copper Recovery= 100*(b/a)(a-c/b-c)

=100*(31/11.8) * [(11.8-4.7)/(31-4.7)

= 100*2.627*0.2699

= 70.91 % of Cu

(Part C) - Cleaner Tailings

The percentage recovered in final process = 100*(a-c)/(b-c)

= 100 *(11.8-4.7)/(31-4.7)

= 100*0.2699

= 26.99 by weight percentage

circulating load of cleaner = 250* 26.99%

= 6747.5/100

= 67.47

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.