Total- 50 points Problem 81: Ch10 Refrigeration Cycle refrigeration cycle that R
ID: 3278929 • Letter: T
Question
Total- 50 points Problem 81: Ch10 Refrigeration Cycle refrigeration cycle that Refrigerant 22 is the working fluid in an idea communicates thermally with a cold region at 40 °C and a warm region at 20 vapor enters the compressor at mass flow rate of the refrigerant is 0.30 kg/s. I vapor-compression saturated -40 °C and saturated liquid leaves the condenser at 20 "C. The Tl Temperature of warm region Condenser Temperature of cold region valveCompressor Evaporalor Saturated or superheated vapor (a) Fill the table below (10 points, 2 points for each blank cell): 10 Points To save time, use the closest value in Tables. NO interpolation is required. StateC) (bar) (kJ/kgK) (kJ/kg) - 40 2 X. 20Explanation / Answer
For isenthalpic process h3 = h4
so h4 = 224.06 KJ/Kg
COP Refg = (h1-h4) / (h2-h1)
COPRefg = (388.13-224.06) / (443.7-388.13)
COPRefg = 2.952
given mass flow rate = 0.3 Kg/s
Refrigeration capacity = m(h1-h4)
= 0.3Kg/s * (388.13-224.06) KJ/Kg * (1/3.516) Ton/KJ/s
= 14 ton
COPR Carnot = TL / (Th-TL)
TL= 273-40=233 K
Th= 273+20=293 K
COPRCarnot = 233/(293-233) = 3.883
State T (c) P(bar) S(KJ/KgK) h(KJ/Kg) comments 1 -40 X 1.8231 388.13 Saturated vapour(Sg1 , hg1) 2 60 9.1002 1.8231 443.7 super saturated at P3 and Sg1 3 20 9.1002 X 224.06 Saturated liquid(hf3) 4 -40 X X X XRelated Questions
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