A 1.45 kg block at rest on a tabletop is attached to a horizontal spring having
ID: 3279169 • Letter: A
Question
A 1.45 kg block at rest on a tabletop is attached to a horizontal spring having constant 17.7 N/m. The spring is initially unstretched. A constant 25.5 N horizontal force is applied to the object causing the spring to stretch. The acceleration of gravity is 9.8 m/s. Find the speed of the block after it has moved 0.226 m from equilibrium if the surface between block and tabletop is frictionless. Answer in units of m/s. Find the speed of the block after it has moved 0.226 m from equilibrium if the coefficient of kinetic friction between block and tabletop is 0.157. Answer in units of m/s.Explanation / Answer
net force at any time=25.5-kx
accleration=(25.5-kx)/1.45=17.6-12.2x
we know
adx=vdv
(17.6-12.2x)dx=vdv
integrating both sided
17.6x-6.1x^2=v^2/2
at x=0.226m
we got
v=2.7 m/s
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.