For DIRECTION, Choose only from these: right (rightarrow), left (leftarrow), tow

Question

For DIRECTION, Choose only from these: right (rightarrow), left (leftarrow), toward the top (toparrow), toward the bottom (downarrow) into the paper (circledtimes), out of the paper (circleddot), UNDETERMINE (for a zero magnitude vector), or NONE (for a scalar). A coil has a magnetic dipole moment 3.3 A middot m^2 into the paper (circledtimes). It is in a very large uniform magnetic field 22 T out of the paper (circleddot). Find the torque the field exerts on the coil. VECTOR EQUATION USED SOLUTION ANSWER I find the magnitude using I am using phi = (Put symbols in the above blanks) (Put a number above for phi.) MAGNITUDE DIRECTION We see the edge of a 66 turn flat circular coil of area 0.0055 m^2 in magnitude. The eye (not ours) looks along the coil's axis, "seeing" a clockwise current of 9.1 A. Find the coil's magnetic dipole moment (with our "DIRECTION" answer relative to the paper, not relative to the eye, so our answer is either right (rightarrow)). VECTOR EQUATION USED SOLUTION ANSWER MAGNITUDE DIRECTION An electron is moving to the left (leftarrow) at 2.9 times 10^8 m/s through a very large magnetic field of 22 T out of the paper (circleddot). Find the force the magnetic field exerts on the electron. VECTOR EQUATION USED SOLUTION ANSWER I find the magnitude using = (sin) (Put symbols in the above blanks) I am using phi = upsilon vector times B vector's ______. (Put a number above for phi.) MAGNITUDE DIRECTION A uniform magnetic field makes an angle of 56.7 with a flat surface. Thus the magnetic filed makes an angle of 90.0 degree - 56.7 degree = 33.3 degree with a normal to the surface. The area of the surface is 5.5 times 10^-5 m^2. The resulting magnetic flux through the surface is 4.44 mu Wb. Calculate the magnitude field. EQUATIONUSED (ONE EQUAL SIGN) SOLUTION ANSWER A straight wire segment is 2.54 cm long and carries a large current of 99 A to the left (leftarrow) through a very large uniform magnetic field of 22 T out of the paper (circleddot) Find the force exerted by the field on the segment. 1 find the magnitude using = (sin) I am using phi = (Put symbols in the above blanks) (Put a number above for phi) MAGNITUDE DIRECTION

Explanation / Answer

According to the question provided I can see you have answered first four questions...So I am solving question no 5) Last question .

5) length = 2.54 cm long I = 99 Ampere B = 22.0 T ==================================Provided values

We need to find the value of the force exerted by the field on the segment.

Formula we are using is : F = B*i * l * sin (theta ) ( Here theta =90 deg )

F= 22 T * 99 A * 0.0254 m = 55.3212 Newton ==============================ANSWER)

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