Problem 2.28- Enhanced - with Feedback Part A When jumping, a tea rapidy extends
ID: 3279743 • Letter: P
Question
Explanation / Answer
Here ,
speed , u = 1 m/s
distance , d = 0.50 mm
d = 5 * 10^-4 m
part A) let the acceleration is a
Using third equation of motion
v^2 - u^2 = 2 * a * d
1^2 - 0^2 = 2 * a * 5 *10^-4
a = 1000 m/s^2
the acceleration is 1000 m/s^2
b)
let the time taken is t
time taken = (v - u)/a
time taken = (1)/1000
time taken = 0.001 s
the time taken is 0.001 s
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