3. The figure below shows a thin lens with a focal lens of 100 mm and a diameter

Question

3. The figure below shows a thin lens with a focal lens of 100 mm and a diameter of 25 mm. Three collimated beams at different angles are incident on the lens and focus onto a sensor. The sensor has a height of 5 mm. The whole system is enclosed in a rectangular box. 100 mm 25mm Sensor 5mm Enclosure Box a. What is the volume of the enclosure box? Draw a reduced tunnel diagram on the figure for a right prism with refractive index n 1.5. The back surface of the reduced tunnel diagram is 10 mm from the sensor. The height of the reduced tunnel diagram should be just large enough to pass all of the rays. -_-# 2 -· Reduced Tunnel Diagram b. What is the required height of the front side of the prism in order to pass all of the rays? c. What is the distance from the thin lens to the front face of the prism? Modify the figure to a regular tunnel diagram (i.e. not a reduced tunnel diagram) Tunnel Diagram

Explanation / Answer

A) 25 mm x 25 mm x 100 mm = 62500 mm3

B) From similar triangles

(10/100) = [ {(25 - a) / 2} / {100 (10 + (a/n) }

Solving gives, a = 8.077 m

C) The distance from the thin lens to the front of the prism face is

100 - (10 + (8.077/1.5)) = 84.615 mm

D) From the figure with the tunnel diagram, the new distance

84.615 + 8.077 + 10 = 102.692 mm

so the sensor has shifted 2.692 to the right.

E) 84.615 + 8.077 = 92.692 mm

F) The sensor is now located 10 mm above the top face of the right prism, which ends up being 1.539 mm above the top edge of the thin lens.

(25 + 1.539) × 25 × 92.692 = 61497.7 mm3

Please rate my answer if you find it helpful, good luck...

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