George pulls a 50kg sled to the right with a force of 85 N. The magnitude of the

Question

George pulls a 50kg sled to the right with a force of 85 N. The magnitude of the frictional force acting on the sled is 56 New. A) what is the magnitude of the normal force acting on the sled? B) what is the acceleration of the sled? George pulls a 50kg sled to the right with a force of 85 N. The magnitude of the frictional force acting on the sled is 56 New. A) what is the magnitude of the normal force acting on the sled? B) what is the acceleration of the sled? A) what is the magnitude of the normal force acting on the sled? B) what is the acceleration of the sled?

Explanation / Answer

Given,

m = 50 kg ; Fp = 85 N ; Ff = 56 N

A)The normal force will be:

N = mg

N = 50 x 9.81 = 490.5 N

Hence, N = 490.5 N

B)The net force atcing is:

Fnet = Fp - Ff

Fnet = 85 - 56 = 29 N

Fnet = ma =. a = Fnet/m

a = 29/50 = 0.58 m/s^2

Hence, a = 0.58 m/s^2

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