iPad 12:08 PM flipitphysics.com 45% alfomia State University Fresno Homework: Fo

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iPad 12:08 PM flipitphysics.com 45% alfomia State University Fresno Homework: Forces And Free-Body Diagrams Hanging Masses Tennis Ball Hanging Masses 2 Loop-the Loop Two Masses Over Pulley Block tennis ball connected to a string spun around in a vertical, circular path at a uniform speed. The ball has a mass m- 0.154 kg and moves at v-4.9 m/s. The circular path has a radius of R- 1.02 1) What is the magnitude of the tension in the string when the ball s at the bottom of the cirelet Pushing Blocks 2) What is the magnitude of the tension in the string when the ball is at the side of the cirdle Satellite in Orbit 2 3, what the magnitude of the tension in the straig when the ball is at the top of the crde? 4 hat is the mimm velocity so the string will not go siack as the bail moves around the circle 5, Below s some space to wite notes on this problem Copyright o 2017 Freeman Worth Pulishers a division of Macmitian Leaming About 1 Tech Support Find Your Local Saie Rep Terms Of Use 1 Privacy Policy | m milan

Explanation / Answer

Here ,

R = 1.02 m

m = 0.154 Kg

v= 4.9 m/s

centripetal force , Fc = m * v^2/R

Fc = 0.154 * 4.9^2/1.02

Fc = 3.63 N

1) magnitude of the tension = mg + m * v^2/R

magnitude of the tension = 0.154 * 9.8 + 0.154 * 4.9^2/1.02

magnitude of the tension = 5.13 N

2) at the side of circle

magnitude of the tension = sqrt(3.63^2 + (0.154 * 9.8)^2)

magnitude of the tension = 3.93 N

3)

at the top of the circle

magnitude of the tension = -mg + m * v^2/R

magnitude of the tension = -0.154 * 9.8 + 0.154 * 4.9^2/1.02

magnitude of the tension = 2.12 N

4)

minimum velocity at the top = sqrt(R * g)

minimum velocity at the top = sqrt(1.02 * 9.8)

minimum velocity at the top = 3.16 m/s

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