9.[1pt] In the Figure, a block m sits on a table. There is static friction betwe
ID: 3280409 • Letter: 9
Question
9.[1pt] In the Figure, a block m sits on a table. There is static friction between block and table. Block m2 hangs from a knot, as shown. Call the tension in the rope connecting the knot to mi T1". Call the tension in the rope connecting the knot to m2, "T2". Call the tension in the third rope (the one tipped up by an angle theta, connecting the knot to the wall), "T3". The system is in equilibrium Which of the following statements are true? (If A and E are true, and the others are not, enter TFFFT) ml m2 A) The force of static friction on ml equals Ti B) The net force on the knot is upwards C) If the table was completely frictionless, the system as shown could still be in equilibrum. D) T3 is equal in magnitude to T2 E) The tension T2 is smaller than m2g Answer: Submit AII Answers 10.l1pt] In the previous problem, block mi weighs 886 N. The coefficient of static friction between the block and the table is 0.27 and the angle theta is 33.0°. Find the maximum weight of block m2 for which block mi will remain at rest Answer: Submit All AnswersExplanation / Answer
in horizontal, there is only T1 an static friction.
for equilibrium.
horizontal net force = T1 - static friction = 0
hence True.
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for equilibrium, Fnet = 0
False
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then there will be no force in horizontal on m1 to balance T1.
hence no equilibrium.
False
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T2 - T3 sin(theta) = 0
T2= T3 sin(theta)
T2 is not equal to T3.
T2 < T3
false
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T2 - m2g = 0
T2 = m2 g
False
Ans: TFFFF
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10. fmax = 0.27 m1 g = 233.82 N
T1 = f_max = 233.82 N
Fx_net = T3 cos33 - T1 = 0
T3 = 278.8 N
Fy_net = T3 sin33 - T2 = 0
T2 = W2
W2 = 278.8 sin33 = 151.8 N
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