surface is 0.40, and the CU no horizontal force is applied to the box and the bo
ID: 3280839 • Letter: S
Question
surface is 0.40, and the CU no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on it? (b) What is the magnitude 45. of the friction force if a monkey applies a horizontal force of 6.0 N Wa to the box and the box is initially at rest? (c) What minimum hori- co zontal force must the monkey apply to start the box in motion? (b) (d) What minimum horizontal force must the monkey apply to blo keep the box moving at constant velocity once it has been started? (m: (e) If the monkey applies a horizontal force of 18.0 N, what is the magnitude of the friction force and what is the box's acceleration?g 5.29 A 45.0-kg crate of tools rests on a horizontal floor. You exert a gradually increasing horizontal push on it, and the crate just begins to move when your force exceeds 313 N. Then you must reduce your push to 208 N to keep it moving at a steady 25.0 cm/s. (a) What are the coefficients of static and kinetic fric- tion between the crate and the floor? (b) What push must you exertExplanation / Answer
Mass of the tools = 45 kg
Maximum force required to push it = 313 N
Friction force = us N where us is the coefficient of static friction
and N is the normal reaction of the surface
N = Mg = 45*9.81 = 441.45 N
us = Maximum force/Normal reaction = 313 /441.45 = 0.71
When it is moving its kinetic friction of coefficient uk
F = 208 = ukN
uk = 208/441.45 = 0.471
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