R1 a R1 83 E1 R1 2 R1 As shown in the figure, the resistances are R1 = 10.0 and

Question

R1 a R1 83 E1 R1 2 R1 As shown in the figure, the resistances are R1 = 10.0 and R2 20.0 , and the ideal batteries have emfs E1 = 5.0 v, and E2 = E3 = 10.0 V. what is the size and direction of the current in battery 1 (take positive current as that flowing through the battery from to )? Submit Answer Tries 0/10 what is the size and direction of the current in battery 2 (take positive current as that flowing through the battery from-to ? Submit Answer Tries 0/10 What is the size and direction of the current in battery 3 (take positive current as that flowing through the battery from - to +)? Submit Answer Tries 0/10 What is the potential difference Va - Vb Submit Answer Tries 0/10

Explanation / Answer

Applying KVL through first loop and second loop,

E1 - i1R1 - (i1 +i2) R2 - E2-i1R1 =0

E3 - i2 R1 - (i1 +i2) R2 - E2-i2R1 =0

Putting the values, 5-10i1 - 20(i1+i2) - 10- 10i1 =0

and 10 - 10i2 - 20*(i1+i2) - 10 - 10i2

Solving the equations i1= - 1/6 A = - 0.1667 A

and i2 = 0.0833A

Current i1 = - 0.1667 A answer

B) current = - (-1/6+1/12) = 1/12 = 0.0833 A

C) current = i2 = 0.0833 A

D) Va-Vb = E2 +(i1+i2) R2 = 10 + (1/12-1/6)*20 = 8.333 V

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