PNTSIS 125 Seead Her Physes f Engineers Light bultb A when both bulb, te rated a

Question

PNTSIS 125 Seead Her Physes f Engineers Light bultb A when both bulb, te rated al 60 #Aaw and light bulb Bi..ated ar1oo w Both are designed to operate ae1mw are tn a cincuit they were gned o, which satement is ct a preater resistance and smaller current than the 100 W hl both bulbs (a) The 60 W hulb has (b) The 60 W builb has a smaller resistance (c) The 60 W bulb greater resistas and smaller curreet than the 100 W has a greater resistance and greater curreat than the 100 W bul ) The 60 W id) The 60 w (e) We bulb has a semaller resistance and greater current than the 100 W buth a need to know the resistivities of the filaments to answer this question ANSWER 2. Which set of equiposential surfaces matches this electrie field so v ov o v so v oy th) o v o V V ANSWER! 3. A parallel plate capacitor of capacitance Co has plates of area A with separation d between them. When it 16-st has charge of magnitude Qo on its plates. It is then disconnected scharging them. After the isconnected to a battery of voltage from the battery and the plates are pulled apart to a separation 2d without di plates are 2d apart, the new capacitance and the potential difference between the plates are ANSWER 4. A perfectly conducting metal sphere of radius R, which carries a net positive charge, +q, sits near a smaller perfectly conducting metal sphere of radius R/3, which is neutrally charged. Then the two spheres are connected together by a thin conducting wire. Afterwards (a) The charges on and the potentials of the spheres are the same as before the wire was connected. (b) Both spheres are at the same potential, but the larger carries the greater positive charge. (c) Both spheres are at the same potential, but the smaller carries the greater positive charge (d) The larger sphere is at a higher potential than the smaller sphere and both spheres carry the same charge. (e) Both spheres are at the same potential and both carry the same charge ANSWERI (S page total:

Explanation / Answer

1) The 60W bulb has a greater resistance and smaller current than the 100 W bulb. So option A is correct.

Explanation

Since it has minimum power, P=VI As voltage is constant as given, hence I will decrease And according to ohm law R=V/I So as current decrease, resistance will increase

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