Jump to... saplingLearning Map A horizontal circular platform rotates counterclo
ID: 3281162 • Letter: J
Question
Jump to... saplingLearning Map A horizontal circular platform rotates counterclockwise about its axis at the rate of 0.809 rad/s. You, with a mass of 74.5 kg, walk clockwise around the platform along its edge at the speed of 1.07 m/s with respect to the platform. Your 20.1-k e also walks clockwise aro the platform, but along a circle at half the latform's radius and at half your linear speed with respect to the platform. Your 18.9-kg mutt, on the other and, sits still on the platform at a position that is 3/4 of the platform's radius from the center. Madel the platform as a uniform disk with mass 92.5 kg and radius 1.85 m. Calculate the total angular momentum of the system Number 251.69 kg- m/s There is a hint available! on the divider bar again to hide CloseExplanation / Answer
w = 0.809 rad/s
for You:
v wrt platform = -1.07 m/s
v wrt ground = - 1.07 + (.809 x 1.85) = 0.427 m/s
for pooodle ,
v wrt platform = - 0.535 m/s
v ground = - 0.535 + (1.85 x 0.809) = 0.962 m/s
for Mutt:
v = (0.809)(3 x 1.85 / 4) = 1.122 m/s
I = I w Or m v r
I = (92.5 x 1.85^2 /2 )(0.809) + (74.5 x 0.427 x 1.85) + (20.1 x 1.85/2 x 0.962) + (18.9 x 1.122 x 1.85)
I = 244 kg m^2 / s .......Ans
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