BD WeBWork - 2018Summe x WeBWorK: TracognaMA C Chegg Study|Guided Sc x C Determi
ID: 3283358 • Letter: B
Question
BD WeBWork - 2018Summe x WeBWorK: TracognaMA C Chegg Study|Guided Sc x C Determine Which Of The ? Secure Q ? https://webwork2 asu.edu/webwork2/Tracogna MAT 343 ONLINE A Summer 2018/Section 3.2 Subspaces/6/?key:NbMQZLaH40MerLMKAHaSNzdNwO5zTNG&us.; Rent BuyTextbooks G Google H How to determine a-Java Game Program ? Account Summary Apps Courses Homework Sets FSAID ASURITESign-in Java Platform Stan i Exercise 3 of Lesson Section 3.2 Subspaces: Problem 6 Section 3.2 Subspaces Problem 6 User Settings Previous Problem List Next Grades (1 point) b-2d 5b+d b+3d Problems Let W be the set of all vectors where b and d are real Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Determine if W is a vector space and check the correct answer below. A. W is not a vector space because it does not have a zero element. B. W is a vector space because it can be expressed as W-span {v, ,. . . , vn} C. W is not a vector space because it does not have additive closure D. W is a vector space because it contains the zero element. Preview My Answers Submit Answers You have attempted this problem 0 times You have 2 attempts remaining. Email instructor Page generated at 05/28/2018 a08:58pm MST O Type here to search 11:56 PMM 5/28/2018 ?Explanation / Answer
Answer is option C. From the given W, it can be dissolved into 2 4X1 vectors [1 5 1 0]T and [-2 1 3 1]T. We cannot represent all the 4 dimensional vectors as a linear combination of these two vectors. For example [1 1 1 1]T cannot be expressed as a linear combination of the above two vectors. This means, it doesnot have additive closure. So, W is not a vector space.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.