1- Arbitron Media Research Inc. conducted a study of the iPod listening habits o
ID: 3289379 • Letter: 1
Question
1-
Arbitron Media Research Inc. conducted a study of the iPod listening habits of men and women. One facet of the study involved the mean listening time. It was discovered that the mean listening time for men was 35 minutes per day. The standard deviation of the sample of the 10 men studied was 8 minutes per day. The mean listening time for the 11 women studied was also 35 minutes, but the standard deviation of the sample was 15 minutes. At the .10 significance level, can we conclude that there is a difference in the variation in the listening times for men and women? (Round your answer to 3 decimal places.)
The test statistic is .
2-
The following are four observations collected from each of three treatments. Test the hypothesis that the treatment means are equal. Use the .05 significance level.
Compute SST, SSE, and SS total and complete the ANOVA table. (Round SS, MS and F values to 2 decimal places.)
3-
A senior accounting major at Midsouth State University has job offers from four CPA firms. To explore the offers further, she asked a sample of recent trainees how many months each worked for the firm before receiving a raise in salary. The sample information is submitted to MINITAB with the following results:
Reject H0 if F > . (Round your answer to 2 decimal places.)
Arbitron Media Research Inc. conducted a study of the iPod listening habits of men and women. One facet of the study involved the mean listening time. It was discovered that the mean listening time for men was 35 minutes per day. The standard deviation of the sample of the 10 men studied was 8 minutes per day. The mean listening time for the 11 women studied was also 35 minutes, but the standard deviation of the sample was 15 minutes. At the .10 significance level, can we conclude that there is a difference in the variation in the listening times for men and women? (Round your answer to 3 decimal places.)
Explanation / Answer
1)
Two-Sample T-Test and CI
Method
Equal variances are assumed for this analysis.
Descriptive Statistics
Estimation for Difference
Test
Test statistic = 0 , as X1bar = X2bar
and p-value = 1 >> 0.10
hence we fail to reject the null hypothesis and we conclude that there is not a difference in the variation in the listening times for men and women
2)
df1= 2 , df2 = 9
P(F >c) = 0.05
c = 4.26
hence reject H0 if TS> 4.26
One-way ANOVA: Treatment 1, Treatment 2, Treatment 3
Method
Equal variances were assumed for the analysis.
Factor Information
Analysis of Variance
Model Summary
Means
Pooled StDev = 1.19024
3)df1 = 5 , df2 =12 ,
P(F <c) = 0.95
c =3.11
hence Reject H0 if F > 3.105875
Please rate my solution
: mean of Sample 1 µ: mean of Sample 2 Difference: - µRelated Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.