M&M; plain candies come in various colors. According to the M&M;/Mars Department

Question

M&M; plain candies come in various colors. According to the M&M;/Mars Department of Consumer Affairs, the distribution of colors for plain M&M; candies is as follows. Color Percentage Red Orange 20% 17% 17% 8% 6% 9% 23% Suppose you have a large bag of plain M&M; candies and you choose one candy at random. (a) Find Pgreen candy or blue candy). Are these outcomes mutually exclusive? Why? No. Choosing a green and blue M&M; is possible. No. Choosing a green and blue M&M; is not possible. Yes. Choosing a green and blue M&M; is not possible. Yes. Choosing a green and blue M&M; is possible. (b) Find P(yellow candy or red candy)

Explanation / Answer

Solution:-

P(green candy or blue candy) = P(Green candy) + P(blue candy)

= 0.06 + 0.09 = 0.15

P(yellow candy or red candy) = P(Yellow candy) + P(Red candy)

= 0.17 + 0.20 = 0.37

P(not purple candy) = P(Candy) - P(Purple)

= 1 - 0.17 = 0.83

(a) 3 to 9 = 112/ 282 = 0.3971

(b) 30 or more = (34+28+10) / 282 = 0.2553

(c) 3 to 49 = (114 + 96 + 34) / 282 = 0.865

(d)10 to 74 = (96+34+28) / 282 = 0.5603

(e) 75 or taller = 10 / 282 = 0.0355

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Rolling to fair dice, one green and one red.

P(getting sum of 6)

S = {(1.5)(2,4)(3,3)(4,2)(5,1)}

Therefore, P(getting sum of 6) = 5/36

P(getting sum of 4)

S = {(1.3)(2,2)(3,1)}

Therefore, P(getting sum of 4) = 3/36 or 1/12

P(getting sum of 6 or 4) = 5/36 + 3/36 = 8/36

Yes, outcomes are mutually exclusive.

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