The ANOVA test performed for determined that not all mean commute times across t

Question

The ANOVA test performed for determined that not all mean commute times across the four cities are equal. However, it did not indicate which means differed. To find out which population means differ requires further analysis of the direction and the statistical significance of the difference between paired population means. Tukey 95% confidence intervals are shown below.

Which of these pairs of cities shows a significant difference in average commute times to work?

Lower Upper Tukey's 95% confidence intervals Houston – Charlotte 11.22 63.78 Houston – Tucson 23.05 75.62 Houston – Akron 37.05 89.62 Charlotte – Tucson –14.45 38.12 Charlotte – Akron –0.45 52.12 Tucson – Akron –12.28 40.28

Explanation / Answer

here option A is correct.

as all other have interval containing values from both sides of 0 ; which shows there differnece is not significant.

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