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Listed below are annual data for various years. The data are weights (metric ton

ID: 3292612 • Letter: L

Question



Listed below are annual data for various years. The data are weights (metric tons) of the linear correlation coefficient r, and find the of imported lemons and car crash fatality rates per 100,000 population. Construct a scatterplot, find the value ffcient evidence to conclude that there is a linear correlation between lemon imports and crash fatality rates? P-value using =005 is there sufficient evidence to conclude that there is a linear correlation between lemon i Do the results suggest that imported lemons cause car fatalities? 265 15.7 481 15.3 532 | 14.9 359 Lemon Imports Crash Fatality Rate 229 15.8 What are the null and alternative hypotheses? OD. H0:=0 Construct a scatterplot. Choose the correct graph below O A. OB. OC. 17 17 17 14 14 14 rt 0 200 400 600 0 200 400 600 200 400 600 200 400 600 The linear correlation coefficient r is Round to three decimal places as needed ) The test statistic t is Round to three decimal places as needed.) The P-value is Round to three decimal places as needed) Because the P-value is l tan the sianificance level 0 05, there sufficient evidence to support the claim that there is a linear correlation between lemon imports and crash Click to select your answer(s)

Explanation / Answer

hypothesis h0:p=0

                   H1:P not equal to 0

OPTION D

scatter plot

option(b) scatterplot

using minitab

Analysis of Variance

Source      DF   Adj SS   Adj MS F-Value P-Value
Regression   1 0.46757 0.46757    34.70    0.010
lemon      1 0.46757 0.46757    34.70    0.010
Error        3 0.04043 0.01348
Total        4 0.50800


Model Summary

       S    R-sq R-sq(adj) R-sq(pred)
0.116087 92.04%     89.39%      74.41%


Coefficients

Term           Coef   SE Coef T-Value P-Value   VIF
Constant     16.388     0.172    95.11    0.000
lemon     -0.002593 0.000440    -5.89    0.010 1.00

The value of R is: -0.9594.

test statistic value          -5.89

p value 0.010

p values lessthan 0.05 there is enough evidence...

The value of R is: -0.9594. (- sign indicates.....)

option B

t value

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