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Take a Test-Stephanie Ortiz Google Chrome Secure /www.mathxl.com/Student/Pla Test aspx?testid = 1 6083 3249&centerwinye; MAT 167 Prin. of Stats SU17-SCHAEFFLER ONLINE 1 Stephanie Ortiz 7/27/17 9:06 PM Test Test #4 Time Limit: 01:00:00 Submit Test This Question: 1 pt 4 of 7 (2 complete) This Test: 7 pts possible Question Help A waitress believes the distribution of her tips has a model that is slightly skewed to the left, with a mean of $8.90 and a standard deviation of $6.90. She usually waits on about 30 parties over a weekend of work. a) Estimate the probability that she will earn at least $300 b) How much does she earn on the best 5% of such weekends? a) P(tips from 30 parties > $300)= (Round to four decimal places as needed.) -D b) The total amount that she earns on the best 5% of such weekends is at least $ (Round to two decimal places as needed.) Enter your answer in each of the answer boxes Type here to search 10006 PM /27/2017

Explanation / Answer

Mean is 8.9 and standard deviation is 6.9

a) From each party she earns 300/30=10 tips thus P(x>10)=P(z>(10-8.9)/6.9)=P(z>0.16) or 1-P(z<0.16) , form normal distribution table we get 1-0.9452= 0.0548

b) P(x>X)=0.05

for 0.05, the z value can be calculated using 0.95 probability. this gives 1.65

Thus 8.9+1.65*6.9=20.285

For 30 parties it will be 30*20.285= 608.55

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