7. Use technology and the given confidence level and sample data to find the con

Question

7.

Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu. Assume that the population does not exhibit a normal distribution. Weight lost on a diet: 99% confidence n=51 x overbar=2.0 kg s=4.1 kg

What is the confidence interval for the population mean ?

__kg<<__ (Round to one decimal place as needed)

Is the confidence interval affected by the fact that the data appear to be from a population that is not normally distributed?

A.No, because the population resembles a normal distribution.

B.Yes, because the sample size is not large enough.

C.No, because the sample size is large enough.

D. Yes, because the population does not exhibit a normal distribution.

Explanation / Answer

Confidence Interval = [ x^ - Z*s/n, x^+z*s/n],

given x ^=2.0

s=4.1

n =51

df =51-1=50 99% confidence interval Z(1-0.99)/2 =2.4033 from t table'

keeping these values in above equation

= [2 - 2.4033*4.1/51, 2+2.4033*4.1/51]

=[2-1.3797,2+1.9737]

=[0.6203,3.9737]

rounding to one decimal point

=[0.6 , 4 ]

0.6 kg < µ < 4 kg

No, because the sample size is large enough.

so option c

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