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In a sample of 1200 U.S. adults, 198 dine out at a restaurant more than once per

ID: 3294244 • Letter: I

Question

In a sample of 1200 U.S. adults, 198 dine out at a restaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is of all U.S. adults, complete parts (a) trough (d) (a) Find the probability that both adults dine out more than once per week The probability that both adults dine out more than once per week is (Round to three decimal places as needed) (b) Find the probability that neither adult dines out more than once per week The probably that neither adult dines out more than once per week is (Round to three decimal places as needed) (c) Find the probability that at least one of the two adults dines out more than once per week The probability that at least one of the two adults dines out more than once per week is (Round to three decimal places as needed) (d) Which of the events can be considered ? Explain Select all that apply A. The event in part (c) is unusual because its probability is less than or equal to 0.05 B. The event in part (a) is unusual because probability is less than or equal to 0.05 C. None of these events are unusual

Explanation / Answer

here the figure 198 is fuzzy please revert if it is different from that

a)probability =(198/1200)*(197/1199)=0.027

b)probability =(1-198/1200)*(1-198/1199)=0.697

c)probability =1-P(none goes out) =1-0.697=0.303

d)option B is correct

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