Please show work Do different types of hospitals have different practices when s
ID: 3295704 • Letter: P
Question
Please show work
Explanation / Answer
The value of the test statistics is 9.48773
Here the degrees of freedom = (3-1)*(3-1) = 4
We use excel to find the p-value
=chidist(9.48773,4)
= 0.05
p-value = 0.05
Here the p-value is less than the level of significance (0.10); we reject the null hypothesis.
Yes. Since the p-value of the test is less than the stated alpha level of 0.10, there is sufficient evidence to reject the null hypothesis that hospital type and insurance claim status are unassociated.
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