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In semester 2, 2016 there was an incident which involved draft answers for part

ID: 3295951 • Letter: I

Question

In semester 2, 2016 there was an incident which involved draft answers for part of a student's STATS 10x assignment being put online to "help" other students with their study for the assignment. The link to this information was then widely spread amongst the students. Unfortunately, many students decided the easiest way to get help was to cut-and-paste (or otherwise copy) portions of this work rather than use it to guide them. Even more unfortunately, as we do not tolerate copying, we ended up with 117 students losing some or all marks for the assignment (which affected their final grades) and all of these students having their names entered on the Register of Academic Misconduct. This exercise was stressful for all concerned and cost a huge amount of staff time to process. The only good thing to come from this is we now have some data for a question! Of the 1717 students enrolled in STATS 10x at the time of this incident, 404 failed the mid- semester test (it was a slightly harder test than usual). Of the 117 students that were caught for academic misconduct, 43 failed the mid-semester test. (a) Construct a two-way table of counts displaying this information. Complete the table. (b) What proportion of the students who failed the mid-semester test were caught for academic misconduct? (c) How many times as likely was it for a student who failed the test to get caught for academic misconduct than it was for a student who passed the test?

Explanation / Answer

(a)                                         Passed                Failed                 Total

      caught for acdemic misconduct               74                     43                     117

Not caught for academic misconduct              1239                  361                   1600

Total                                                             1313                     404                1717

(b) P(failed & caught) = 43/1717 = 0.0250

(c) P(passed) = 1313/1717 = 0.7547

Ratio = 0.0250/0.7547 = 0.0331

So, it was 3 times than 100

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