In a random sample of 40 refrigerators, the mean repair cost was $146.00 and the

Question

In a random sample of 40 refrigerators, the mean repair cost was $146.00 and the population standard deviation is $15.30. Construct a 95% confidence interval for the population mean repair cost. Interpret the results. Construct a 95% confidence interval for the population mean repair cost. The 95% confidence interval is (). (Round to two decimal places as needed.) Interpret you results. Choose the correct answer below A. With 95% confidence, it can be said that the confidence interval contains the true repair cost. B. With 95% confidence, it can be said that the confidence interval contains the sample mean repair cost. C. The confidence interval contains 95% of the mean repair costs.

Explanation / Answer

Margin of error = 1.960*15.30)/Sqrt(40) = 4.741432

95% Interval

(146-4.741432, 146+4.741432)

=(141.26, 150.74)

Interpret

Option A is Correct

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