A carton of 23 eggs contains 3 eggs that are cracked. Suppose two of the eggs ar

Question

A carton of 23 eggs contains 3 eggs that are cracked. Suppose two of the eggs are inspected at random and without replacement. (That is, you are drawing eggs one at a time. When you draw, all eggs that have already been drawn have been removed from the carton What is the probability that the first egg selected is cracked? What is the probability that the second egg selected is cracked given that the first one selected was cracked? What is the probability that both eggs chosen are cracked? What is the probability that all three eggs are cracked?

Explanation / Answer

probability that first egg selected is cracked =3/23

probability that second egg selected is cracked given first was cracked =2/22=1/11 (as there remains 2 cracked eggs out of 22 if first one was cracked)

probability that both eggs chosen are cracked =(3/23)*(1/11) =3/253

probability that all 3 are cracked =(3/23)*(1/11)*(1/21) =1/1771

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.