If a couple were planning to have three children, the sample space summarizing t
ID: 3299322 • Letter: I
Question
Explanation / Answer
A) sample space s : bb,gg,bg,gb
B) Probability of getting two green eyed children = P(gg) = 1/4 = 0.25
C) Probability of getting one blue eyed child and one green eyed child
= P(gb or bg) = 2/4 = 0.5
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