A common concern of parents is the language development of their child. Say a pa

Question

A common concern of parents is the language development of their child. Say a parent brings 5-yr-old John for an assessment, and John is given Language and Intelligence tests. He gets 96 correct answers on the Language test and 61 correct on his Intelligence test. The number of correct Intelligence test answers of children his age is normally distributed with a mean of 50 and a standard deviation of 5. The number of correct Language test answers of children his age is normally distributed with a mean of 103 and a standard deviation of 3.

1. Calculate John's Z scores (using the z score formula) for the Intelligence and Language tests.

2. Based on the Z scores, how much does John compare to his peers in terms of his language? How does John compare to his peers in terms of his intelligence?

3. Using the normal curve table, which percentage of children score above and below John’s language score? Or find it using an online calculator

4. Using the normal curved table, which percentage of children score above and below John’s intelligence score? Or find it using an online calculator

5. What advice would you give John’s parents?

Explanation / Answer

1) John's Z scores for intelligence test =(X-mean)/std deviation =(61-50)/5 =2.2

John's Z scores for language test =(X-mean)/std deviation =(96-103)/3 =-2.3333

2)from above as z score for language is on negative side ; therefore he fares below then average from his peers.

from above as z score for language is on positive side ; therefore he fares above then average from his peers.

3) from table ; % of children score above John’s language score =99.02%

% of children score below John’s language score =0.98%

4)% of children score above John’s intelligence score =1.39%

% of children score below John’s intelligence score =98.61%

5) we advice John’s parents to advice him to work on his language studies.

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