Q: What is the probability that a randomly selected voter favors the school of c

Question

Q: What is the probability that a randomly selected voter favors the school of choice program?

D) P(F) = 0.62

What is the probability that a randomly selected Republican favors the school of choice program?

D) P(R | F) = 0.10

What is the probability that a randomly selected voter who favors the school of choice program is a Democrat?

D) P(F | D) = 0.88

A candidate thinks she has a good chance of gaining the votes of anyone who is a Democrat or who is in favor of the school of choice program. What proportion of the 1000 voters is that?

D) P(D | F) = 0.92

Question (2b)

In a large city, 69% of the people are known to own a cell phone, 29% are known to own a pager, and 17% own both a cell phone and a pager.

Q: What proportion of people in this large city own either a cell phone or a pager?

D) 1.1

What is the probability that a randomly selected person from this city owns a pager, given that the person owns a cell phone?

D) 0.528

Are the events “owns a pager” and “owns a cell phone” independent?

D) Cannot be determined.

Question (2c)

Suppose we roll a red die and a green die. Let A be the event that the number of spots showing on the red die is three or less and B be the event that the number of spots showing on the green die is more than three. The events A and B are

E) None of these.

Question (2d)

The law of large numbers states that, as the number of observations drawn at random from a population with finite mean m increases, the mean J of the observed values

A) P(F) = 0.23 The table below shows the political affiliation of 1000 randomly selected American voters and their positions on the school of choice program: Political Party Republican Other 150 260 Position Democrat 230 30 220 110 Favor Oppose Let the event D = {voter is a Democrat), R = {voter is a Republican), and F3(voter favors the school of choice program). For each of the following questions, write the probability in symbols (e.g., P(D)) and calculate the probability.

Explanation / Answer

1) (C)

EXPLANATION: P(F) = 600/1000 = 0.6

2) (B)

EXPLANATION: P(R/F) = 150/600 = 0.25

3) (A)

EXPLANATION: P(D | F) = 230/600 = 0.38

4) (A)

EXPLANATION: P(D or F) = P(D)+P(F)-(D and F) = (260/1000)+(600/1000)-0 = 0.86

5)(B)

EXPLANATION : P(CorP) = P(C)+P(P)-P(C and P) = 0.69+0.29-0.17 = 0.81

6) (A)

EXPLANATION: P(P/C) = P(P and C)/P(C) = 0.17/0.69 = 0.246

7) (D)

8)Question (2c) (C) (INDEPENDENT)

9) Question (2d) (C) (Gets closer and closer to the population mean m)

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