1. Medical researchers took a simple random sample of 10 males and 10 females to
ID: 3303014 • Letter: 1
Question
1. Medical researchers took a simple random sample of 10 males and 10 females to investigate average body temperatures.
a) Use the Minitab dataset BodyTemp.mtw, to calculate the mean and standard deviation for the body temperature of the randomly sampled males, and the mean and standard deviation for the females. (Hint: Use Stat > Basic Statistics > Display Descriptive Statistics and for Variables, select Males and Females.) Include your Minitab output below (copy and paste).
b) estimate the mean body temperature of males, with a 2-standard deviation margin of error.
c) Estimate the difference in mean body temperature for males versus females using an approximate 95% confidence interval, using Minitab to first calculate the mean and standard deviation for the sample of female body temperatures.
d) Is there evidence that the average body temperature of males differs from the average body temperature of females? Explain your answer.
Males Females 96.9000 97.8000 97.4000 98.0000 97.5000 98.2000 97.8000 98.2000 97.8000 98.2000 97.9000 98.6000 98.0000 98.8000 98.1000 98.8000 98.6000 99.2000 98.8000 99.4000Explanation / Answer
a)
Descriptive Statistics: Males, Females
Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 Maximum
Males 10 0 97.880 0.176 0.555 96.900 97.475 97.850 98.225 98.800
Females 10 0 98.520 0.167 0.527 97.800 98.150 98.400 98.900 99.400
b)
Margin of error = Critical value x Standard deviation
=1.96*0.555
=1.0878
c) d)
Two-sample T for Males vs Females
N Mean StDev SE Mean
Males 10 97.880 0.555 0.18
Females 10 98.520 0.527 0.17
Difference = (Males) - (Females)
Estimate for difference: -0.640
95% CI for difference: (-1.151, -0.129)
T-Test of difference = 0 (vs ): T-Value = -2.64 P-Value = 0.017 DF = 17
p value < 0.05
reject null hyothesis.
We cancluded that there evidence that the average body temperature of males differs from the average body temperature of females
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