The amounts of nicotine in a certain brand of cigarette are normally distributed

Question

The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.899 g and a standard deviation of 0.281 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 39 cigarettes with a mean nicotine amount of 0.827 g Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 39 cigarettes with a mean of 0.827 g or less. P(M

Explanation / Answer

Answers are highlighted in BOLD

Pop. Mean = .899
Stdev = .281
n= 39
Sample Mean = .827

P(M<.827) = P(Z< (.827-.899)/(.281/sqrt(39)) = P(Z<-1.6) = .0548

Based on result above, ( given the cutoff is .0548>.05)
We do not reject null hypothesis, thus:
A. No, The probability of obtaining this data is high enough to have been a chance occurence

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.