Supposing there are 2 Jars.The first Jar has 9 green sweets and 5 purple sweets.

Question

Supposing there are 2 Jars.The first Jar has 9 green sweets and 5 purple sweets.The second Jar has 6 green sweets and 7 pink sweets.2 Jars have same probability of being chosen.

a)Suppose we pick a sweet out of random.What is the probability it is a green sweet.

b)supposing we pick 2 sweets from each of the Jars.Find the probability there are 2 green sweets picked out of the 4 sweets picked.

c)Repeating it again we found 2 green Sweets picked out of the 4.Find the probability one of these 2 green sweets picked is from Jar 1.

Explanation / Answer

a)probability it is a green sweet. =P( first Jar and green sweet+second Jar and green sweet) =(1/2)*(9/14)+(1/2)*(6/13)

=0.5522

b) probability there are 2 green sweets picked out of the 4 sweets picked =P( from first Jar 2 green and from second none+from first 1green and from second 1 green sweet+from first none and from second 2 green sweets)

=(9/14)*(8/13)*(7/13)*(6/12)+2*(9/14)*(5/13)*2*(7/13)*(6/12)+(5/14)*(4/13)*(6/13)*(5/12)=0.3939

c)probability one of these 2 green sweets picked is from Jar 1 ; given 2 green sweets

=P( from first 1green and from second 1 green sweet)/P(2 green sweet)

=2*(9/14)*(5/13)*2*(7/13)*(6/12)/0.3939

=0.6760

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