Firefox File Edit View History Bookmarks Tools Window Help (0-0) : 4) 2496 C) We

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Firefox File Edit View History Bookmarks Tools Window Help (0-0) : 4) 2496 C) Wed 3:22 PM Allis Adimey a Exam 01 Survey: Exam 01 Online Pro... x+ https://www.webassign.net/web/Student/Assignment-Responsesiast?dep.17258485 c Search High level snapshot of the Exam process (1) Log into Webcourses, Start the 'Exam 01 Online Proctor Quiz (2) Answer Question 01 on Webcourses (3) Launch new browser window and sign into Webassign (4) YOU ARE HERE IN THE PROCESS. Start 'EXAM 01' on Webassign. Upon completing 'EXAM 01' on webassign (5) Answer Question 02 on webcourses (6) Now you have FULLY completed 'Exam 01 Online Proctor Your last submission is u Now complete the quiz here and then follow the instructions. You have 75 minutes from when you start the quiz. Students with SAS approval will get twice the time. There are 12 questions. I RECOMMEND YOU TAKE THIS EXAM ON CAMPUS. IT IS YOUR RESPONSIBILITY TO ENSURE YOU HAVE CONTINUOUS INTERNET AND ELECTRICITY 9. Question Details DevoreStat9 2.E.064. My Notes Ask Your Teacher The Reviews editor for a certain scientific journal decides whether the review for any particular book should be short (1-2 pages), medium (3-4 pages), or long (5-6 pages) Data on recent reviews indicates that 50% of them are short, 20% are medium, and the other 30% are long. Reviews are submitted in either word or LaTeX. For short reviews, 80% are in word, whereas 50% of medium reviews are in word and 40% of long reviews are in word. Suppose a recent review is randomly selected (a) What is the probability that the selected review was submitted in Word format? (b) If the selected review was submitted in Word format, what are the posterior probabilities of it being short, medium, or long? (Round your answers to three decimal places.) short medium long Submit Answer Save Progress

Explanation / Answer

a) P(Word format) = 0.5*0.8 + 0.2*0.5 + 0.3*0.4 = 0.62

b) P(Short) = (0.5*0.8)/0.62 = 0.645

P(Medium) = (0.2*0.5)/0.62 = 0.161

P(Long) = (0.3*0.4)/0.62 = 0.194

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