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points Devore Stat9 3 E.012 Airlines sometimes overbook flights. Suppose that fo

ID: 3306050 • Letter: P

Question


points Devore Stat9 3 E.012 Airlines sometimes overbook flights. Suppose that for a plane with SO seats 55 passengers have kets be ne the ran on va able·ast e n eo eckememenom hod a raw emaene o no er enea arte tenet . e - 45 46 47 48 49 50 51 52 53 54 55 p(v) 0.05 0.10 0.13 0.14 0.25 .16 0.06 0.05 0.03 002 0.01 (a) What is the probability that the flight will accommodate all ticketed passengers who show up? (b) What is the probability that not all ticketed passengers who show up can be accommodated? take the e after all ticketed passengers have been accommodated), what is the probability that you wil be able to (c) If you are the first person on the standby list (which means you wil be the first one to get on the plane if there are any seats availabl What is this probability if you are the third person on the standby list? Need Help?eTeth to iter -16 points DevoreStat9 3.E.013

Explanation / Answer

a)

For the flight to accomidate all ticketed passengers who show up, the number of passengers who show up should be atmost 50

Probabitly that the flight will accomodate all ticketed passegers who show up

= P(45)+P(46)+P(47)+P(48)+P(49)+P(50)

= 0.05+0.10+0.13+0.14+0.25+0.16 = 0.83

b)

For the flight to not accomadate all ticketed passengers who show up, the number of passengers who show up should be greater than 50

Probabitly that the flight will not accomodate all ticketed passegers who show up

= P(51)+P(52)+P(53)+P(54)+P(55)

= 0.05+0.06+0.03+0.02+0.01 = 0.17

c)

if the first person in standby list to get into flight the no of ticketed passengers who show up should be less than 50

Probability that first person in standby list to get into flight

= P(45)+P(46)+P(47)+P(48)+P(49)

= 0.05+0.10+0.13+0.14+0.25 = 0.67

d)

if the third person in standby list to get into flight the no of ticketed passengers who show up should be less than 48

Probability that first person in standby list to get into flight

= P(45)+P(46)+P(47) = = 0.05+0.10+0.13 = 0.28