points Devore Stat9 3 E.012 Airlines sometimes overbook flights. Suppose that fo
ID: 3306050 • Letter: P
Question
Explanation / Answer
a)
For the flight to accomidate all ticketed passengers who show up, the number of passengers who show up should be atmost 50
Probabitly that the flight will accomodate all ticketed passegers who show up
= P(45)+P(46)+P(47)+P(48)+P(49)+P(50)
= 0.05+0.10+0.13+0.14+0.25+0.16 = 0.83
b)
For the flight to not accomadate all ticketed passengers who show up, the number of passengers who show up should be greater than 50
Probabitly that the flight will not accomodate all ticketed passegers who show up
= P(51)+P(52)+P(53)+P(54)+P(55)
= 0.05+0.06+0.03+0.02+0.01 = 0.17
c)
if the first person in standby list to get into flight the no of ticketed passengers who show up should be less than 50
Probability that first person in standby list to get into flight
= P(45)+P(46)+P(47)+P(48)+P(49)
= 0.05+0.10+0.13+0.14+0.25 = 0.67
d)
if the third person in standby list to get into flight the no of ticketed passengers who show up should be less than 48
Probability that first person in standby list to get into flight
= P(45)+P(46)+P(47) = = 0.05+0.10+0.13 = 0.28
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