Problem #8: Data from the Central Hudson Laboratory determined that the mean num
ID: 3306413 • Letter: P
Question
Problem #8: Data from the Central Hudson Laboratory determined that the mean number of insect fragments in 225-gram chocolate bars was 14.4 (http://www.centralhudsonlab.com/chocolates.shtml). In a 37-gram bar the mean number of insect fragments would then be 2.37. Assume that the number of insect fragments follows a Poisson distribution (a) If you eat a 37-gram chocolate bar, find the probability that you wil have eaten at least 2 insect fragments. (b) If you eat a 37-gram chocolate bar every week for 10 weeks, find the probability that you will have eaten no insect fragments in exactly 4 of those weeks Problem #8(a): 0.73746405 Problem #8(b): Just Save saved! (Admin Page) Submit Problem #8 for Grading Problem #8 | Attempt #1 | Attempt #2 | Attempt #3 Your Answer: |8(a) 8(b) Your Mark:|8(a) 8(b) 8(a) 8(b) 8(a) 8(b) 8(a) 8(b) 8(a) 8(b)Explanation / Answer
Problem 8a:
P(atleast 2 insects) = 1 - P(0 insects) - P(1 insect) = 1 - e-2.37 - e-2.37*2.37 = 0.68497
Formula for P(k events in interval) = e- *(k/k!)
Problem 8b: P(0 insect) = e-2.37,
P(0 insect exactly 4 weeks) = (e-2.37)4 =0.00007636394
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