ode for this class or purchased access online period vall end Monday, October 2

Question

ode for this class or purchased access online period vall end Monday, October 2 2017 at 12:00 AM EDT. After that date you will no longer be able to see your WebAss According to our records you have not yet redeemed an access c number of authors were classified according to the number of artides they thad published during a certain period. The results were presented in the accompanying frequency distribution: were classified a In a study of author productivity, a large . Nuite, or 1 2 3 4 5 6 7 8 9 10 11 12 13 1516.17 papers Frequency 752 204 27 50 3328-19-19 6 7 )Construct a histogram corresponding to this frequency distribution. Peroent Percent 301 Number Number 0 1 7 11 13 15 o 1 3 5 7 9 1 13 15 Percent Percent 20 Number Number What is the most interesting feature of the shape of the distribution? O normally distributed heavy negative s o slight negative skewness o bimodal O heavy positive sk O slight positive skewness of these authors published at least five papers? At least ten papers? More than ten papers? (Round your answers to four decimal places.) at least five papers at least ten papers more than ten papers (c) Suppose the fve 15s, three 16s, and tiree 17s had been lumped into a single category displayed as 1215. Would you be able to draw a histogram? Explain Yes; this dass does have a finite width of 3, so the relative frequency of category "215" can be plotted as a rectangle of height 0.831 No; the classes cannot be combined in such a manner because the it N; this dass has no upper boundary, so it is impossible to draw a rectangle above it having finite area (ie, frequency). O O increments would not be equivalent (a) Suppose that instead of the values 15, 16, and 17 being listed separately, they had been combined into 15-17 category with frequency 11. Would you be able to draw a histogram? Explain O Yes; this class does havea rinite width o , so Lhe relative frequency of category .is-i7" can be plotted as a rectangle or height o.au. O No: this dless has no upper boundary, so it is impossible to draw a rectangle above it having finite area (i.e., frequency). O No; the classes cannot be combined in such a manner because the increments would not be equivalent Subrmit

Explanation / Answer

a) correct histogram is C)

below left one

b) this is highly positive skewed option E) is correct

c)

P(X>=5)=0.11276

P(X>=10)=0.03054

P(X>10)=0.025058

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