331 242 127 299 340 253 203 251 302 261 235 165 191 337 124 106 123 225 71 335 3

Question

331 242 127 299 340 253 203 251 302 261 235 165 191 337 124 106 123 225 71 335 310 180 206 249 158 145 232 247 121 345 297 280 152 216 264 141 338 167 175 196 209 235 173 176 105 211 300 159 174 174 329 150 272 138 131 287 344 255 238 293 231 233 123 198 195 161 86 119 290 284 139 1 If sampling is done without replacement, the number of possible samples of size n = 6 from the above population is 278.252,668 292,897,545 308,313,205 324,540,216 Arandom sample of sizen-6is selected. The data in the highlighted cells above are shownbelow 180 174 235 238 131 338 2 The mean ofthis sample is: 212 214 216 218 a d 3 The variance of this sample is: a 4335.T b 4682.5 c 5202.8 d 5406.9 4 For the sample means computed from the number of random samples determined in question 1 the expected value or mean of sample means is Use EHcel rather than your calculator to do the calculations a 208.62 b 216.96 c 225.64 d 234.67

Explanation / Answer

1) =COMBIN(81,6) 324540216 option d) is correct data (n=6) 180 174 235 238 131 338 2) mean 216 AVERAGE(A7:A12) 3) var of sample (s^2): 5202.8 VAR.S(A7:A12) 4) by central limit theorem, E(xbar)= 216.96 optio b) is correct

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