Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

n Assignment OURCES Chapter 19, Problem 22 GO blem 04 Charges of -q and +2q are

ID: 3307732 • Letter: N

Question

n Assignment OURCES Chapter 19, Problem 22 GO blem 04 Charges of -q and +2q are fixed in place, with a distance of 2 m between them. A dashed line is drawn through the negative charge, perpendicular to the line between the charges. On the dashed line, at a distance L from the negative charge, there is at least one spot where the total potential is zero. Find L. oblemo2 roblem 12 roblem,13 Problert2 | | L = Problem 27 Problem 29 the tolerance is +/-5% GO TUTORIAL LINK TO TEXT re sults by Study By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. SAVE FOR LATER SUBMIT ANSWER Question Attempts: 0 of 3 used powered by MapleNet All Rights Reserved. A Division of

Explanation / Answer

distance from -q is L meters.

then distance from 2q=sqrt(L^2+3^2)=sqrt(L^2+9)

potential due to a charge at a distance=k*charge/distance

where k=coloumb's constant=9*10^9

so equating total potential to 0 at this point:

(-k*q/L)+(k*2*q/sqrt(d^L+9))=0

==>q/L=2*q/sqrt(L^2+9)

==>sqrt(L^2+9)=2*L

squaring both sides:

L^2+9=4*L^2

==>3*L^2=9

==>L^2=3

==>L=sqrt(3)=1.732 m

so at a distance of 1.732 m , total potential is zero.