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: iPad 2:14 AM 1% Homework: Vectors And 2-D Kinematics Tipler6 1.P.OS4. Rewrite

ID: 3307872 • Letter: #

Question

: iPad 2:14 AM 1% Homework: Vectors And 2-D Kinematics Tipler6 1.P.OS4. Rewrite the following vectors in terms of their magnitude and angle tcountercio inse from thedirection). 1) A dinplacement vector with an x component of +5.7 m and a y component of -5.7m 8.08 Catch 2 21 ange 315 Tiplers 1.P.OS3 Your submissions 315 Computed ae 315 nitted: Wednesday, Januay 31 at 12:15 M Tiplers 1.P.054 Tipler6 3.P.007 3) Avelocity vector with an x component of .57 m/s andycorporern of .16 m/s. magnitude: Thpleró 3.P010. 59 20 Tipler6 3.P.023 Computed walue 39.20 bnitted: Wedneday,January 31 at 12:15 AM .P.047 4) ange Tipler 3.P.072 164.4 Tiplers 3.P.109 Your ubnisuin 1X Computed vaue 164 Subnitted Wednesday, Jaary 31 at 12:16 A 5, A force vector amagitude of 43 b that is in the third quadrant with an x component whose magnitude is 22 6) angle | macmillan Copyright © 201 8 Freeman worenblihers , a division of Marilla, Leaming About iTech Support rnd r Lacal Sales R Terms or usePrivacy Policy

Explanation / Answer

According to the given problem,

4.) The angle of velocity vector,

= Tan-1[-16/-57]

= 180 + Tan-1[16/57] [From x component and y component of velocity it can said that vector is in Q3] and Tan is +ve in this Quadrant.

= 195.68o

5.) Given,

F = 43lb and Fx = - 22lb [As it is in Q3]

Using magnitude formula,

F2 = Fx2 + Fy2

F2y = 1365

Fy = - 36.9459 [as its in Q3]

Fy = - 37 lb.

6.) As we did in question 4.

= Tan-1[-37/-22]

= 180 + Tan-1[37/22] [From x component and y component of Force it can said that vector is in Q3] and Tan is +ve in this Quadrant.

= 239.23o

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