ME 370: Tbermodynamics HW1- A 4-KW resistance heater in a water heater runs for
ID: 3307987 • Letter: M
Question
ME 370: Tbermodynamics HW1- A 4-KW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the amount of electric energy used in both kWh and kJ. HW2- Consider two closed systems A and B. System A contains 3000 kJ of thermal energy at 20°C, whereas system B contains 200kJ of thermal energy at 50°C. Now the systems are brought into contact with each other. Determine the direction of any heat transfer between the two systems. HW3- A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of 3.2 kg and a cross sectional area of 35 cm2. A compressed spring above the piston exerts a force of 150N on the piston. If the atmospheric pressure is 95 kPa, determine the pressure inside the cylinder. HW4- A hydraulic lift is to be used to lift a 2500 kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Determine the diameter of the piston on which the weight is to be placed. Hw5- Fresh water and sea water flowing in parallel horizontal pipelines are connected to each other by a double U-tube manometer, as shown in the figure. (a) Determine the pressure difference between the two pipelines. (b) Repeat this problem by replacing the air with oil whose specific gravity is 0.72. Take the densities of the sea water, and fresh water at that location to be 1035 kg/m, 13600 kg/m, and 1000 kg Air respectively Fresh 40 cm Sea 70 cm 60 cm 10 cm MercuryExplanation / Answer
Solution ;-
Energy = power × time
=4000×3×60×60
= 4.32×10^3 kj
And energy in kWh = 4×3 = 12kwh
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