CODE- GGILAB-ISP209, Spring 2018-The Mys MidTermal Two blocks are in contact on

Question

CODE- GGILAB-ISP209, Spring 2018-The Mys MidTermal Two blocks are in contact on a frietionless table. A- Let's ride the bumper cars, Analyse l force F is applied to M, ns shown. If M,-1.84 wing collisions isvolving bumper cars kg, M 3.00 kg, and F- 4.90 N, find the size of the contact Case 1: Your car (total mass 56 k) is moving at 43 m/s force between the two blocks when it smashes into a stationary car (total mass 67 kg), which bounces off. Alter the collision, your car is still mov- ing forward at 1.1 m/s. Find the speed of the car with which you collided (in s/s) (in N) 20. AO 1.86 p Case 2: This time, your car (total mass 56 kg) Is moving m/s when il smashes into a the back end of another DO 5.68 GO 1.73× 10- EO 8.23 HQ 2.51 × FO 1.19 x101 car (total mass 72 kg) moving in the same direction as you but at the slower speed of 3.2 m/s Somehow, your bumpers lock and you move off together. Find the speed of the car to which you are now connected in s/s) / pt If instead an equal but oppositely directed force is ap- toM1 rather than Mr findthesize ofthe contact force 2S. AO 129 BOi88 do 272 DO 394 between the two blocks EO 572 FO 829 GO 12.02 1O 17 43 BO 1.24 EO 243 21. AO 9.95×10". Case 3: Now, your car (total mass 56 kg) is moving in positive direction a 3.3 m/s and you are racing toward head-on collision. The car approsching you has a mass of 59 kg and is moving in the opposite direction at 4.2 m/s. After pWaich is the uesit of energy ia the International System the olision you find yourself movwlng backward at 2.1 n/s. What is the speed of the other car? fin n/s) 22 AO Celsius (C) BO Tesla (T) CO Watt (W) EO 0.93 FO 1.34 GO 1.95 HO 2.82 DO Ampere (A) EO Joule (J) pt Case 4: OK, now you're all mixed up and you slam into , which physical property determines how an object will wall with your car (total mass 36 kg) moving at 3.1 m/s. You bounce straight back at 1.9 m/s and somebow determine that the time of contact with the wall was 369 ms. What is the magnitude of the force that was exerted on your car? in response to a given force? 23.AO The kinetic energy BO The potential energy CO The velocity DO The mass EO The position in space (in N) 27. AO 1370.95 BO 1823.36 CO 2425.07 DO 3225.35 EO 4289.71 FO 5705.32 GO 7588 08 HO 100214

Explanation / Answer

20]

F = [M1 + M2]a

=> a = F/(M1 + M2) = 4.9/(3+1.84) = 1.012 m/s2

this is the acceleration for both the blocks

now, for M2,

F - R = M2(a)

where, R is the contact force

so, 4.9 - R = 3(1.012)

=> R = 1.863 N [option A].

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