A passenger car weighs 2000 kg and has a wheelbase of 2.79 m. The center of grav

Question

A passenger car weighs 2000 kg and has a wheelbase of 2.79 m. The center of gravity is 1.27 m behind the front axle. If a pair of radial-ply tires, each of which has a cornering stiffness of 45.88 kN/rad, are installed in the front, and a pair of bias-ply tires, each of which has a cornering stiffiess of 33.13 kN/rad, are installed in the rear, determine whether the vehicle is understeer or oversteer. Calculate the critical speed of the vehicle if it exists. Find the neutral steer point and stability margin. What would the steady-state handling characteristics of the vehicle be if the front and rear tires are interchanged?

Explanation / Answer

Wf = (2.79-1.27)kN =1.52 kN

and Wr = 1.27 kN

Kus = Wf/Cf - Wr/Cr

= 1.52/45.88-1.27/33.13

= -0.0052 rad = -0.298 deg

Since Kus is negative, given condition represents oversteer condition.

Critical speed, v = (gb/Kus)^0.5

= (9.8*2.79/0.298*3600)^0.5

= 0.1596 m/s

If the two tyres are interchanged, then

Kus = 1.52/33.13-1.27/45.88

= 0.0182 rad

= 1.04272 deg

So, this is an understeer condition.

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