ssignment-20180205-Part I (Homework) PH 253, sectilon 001, Spring 2018 Istructor
ID: 3308231 • Letter: S
Question
ssignment-20180205-Part I (Homework) PH 253, sectilon 001, Spring 2018 Istructor Jerome Busenite Total Your last subemission is used for your score 33 P044 ) and an in of energy E interacts with an electron at rest and photon + e-e+ +e"+e" A photon The two electrons and the positron move off with identical momenta in the direction of the initial photon. Find the kinetic energy of the three final particles and find the energy E of the photon. (Hint: Conserve momentum and total relativistic energy.) kinetic energy photon energy O Type here to searchExplanation / Answer
Solution :-
Ephoton + MoC^2= 3MoC^2 + 3KE
Ephoton = energy of the photon: hc/lambda
moc^2 = rest mass energy of electron
Ke = kinetic energy of the electrons
K of electron after collision: 2/3mc^2
= 2/3*9.109*10^-31*(3*10^8)^2
= 5.5*10^-20 MeV
initial photon energy : 4mc^2
= 4*9.109*10^-31*(3*10^8)^2
= 3.3*10^-19 MeV
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