7. For the circuit shown below BEFORE YOU SOLVE FOR CURRENTS ANSWER THE FOLLOWIN

Question

7. For the circuit shown below BEFORE YOU SOLVE FOR CURRENTS ANSWER THE FOLLOWING QUESTIONS a. How does I, compare to l2? why? b. How does the voltage across R1 (AVba) compare to the voltage across R2 (AVcb)? Why? c. How does I3 compare to I? Why? d. How does the voltage drop (AVit) compare to the voltage drop (AV)? Why? e. How does the voltage drop (AVif) compare to the voltage drop (AVb)? Why? f. How does L4 compare to I,? Why? g. How does the voltage drop (AVh) compare to the voltage drop (AVed)? Why? i) Now solve for the equivalent resistance and the currents through each resistor in step by step reduction of the circuit. R, 252 at R,-12 12V R2-4 R,-362

Explanation / Answer

7. a. form the diagram we can see that

I1 = I2 ( becuase both these currents are flowing in just one branch of the circuit and hence from kirchoff's junction law they must be equal)

b. voltage drop across a resistor is given by V = iR

hence as current is same through both the resistors hence voltage drop across R2 is double to that of voltage drop across R1

c. now, from ohms law

12 = I1*6

I1 = 2 A

also

12 = 3*I3

I3 = 4 A

hence

I3 is double as compared to I1

d. as i , h and g ar ethe smae points Vgi = 0 V

where as Vfi will have some non zero value

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